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x^2+18x-2880=0
a = 1; b = 18; c = -2880;
Δ = b2-4ac
Δ = 182-4·1·(-2880)
Δ = 11844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11844}=\sqrt{36*329}=\sqrt{36}*\sqrt{329}=6\sqrt{329}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6\sqrt{329}}{2*1}=\frac{-18-6\sqrt{329}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6\sqrt{329}}{2*1}=\frac{-18+6\sqrt{329}}{2} $
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